A 2.241 g preview of nickel react next to oxygen to form 2.852 g of the metal oxide.?
A 2.241 g sample of nickel reacts next to oxygen to form 2.852 g of the metal oxide. Calculate the empirical formula of the oxide.
Answers:
The nickel oxide thus formed has a mass of 2.852 grams, of which
2.241 grams are nickel and the remaining 0.611 gram is oxygen.
To find the mole fraction of each factor, divide its mass in grams
by its atomic weight: for nickel we return with 2.241/58.7 = 0.0381 mole
For the oxygen, divide 0.611 by 16 and we get 0.0381 mole.
These mole fractions are the same, so we hold the elements nickel
and oxygen in a 1 to 1 ratio.
The empirical formula is NiO.
Hope this answers your question. Source(s): college chemistry
Related Questions:
Metal x forms ionic chloride beside the formula xcl3,next wat formula is likly to be that of a staple Sulfi of x?
Aluminum metal react next to aqueous iron(III) oxide to form aqueous aluminum oxide and iron metal.?
What react near Copper (II) Chloride solution to form Copper metal?
Why are metals more feasible to be found within their combined form?
Why do transition metals near d6 low spin electron configuration form adjectives complexes?
Answers:
The nickel oxide thus formed has a mass of 2.852 grams, of which
2.241 grams are nickel and the remaining 0.611 gram is oxygen.
To find the mole fraction of each factor, divide its mass in grams
by its atomic weight: for nickel we return with 2.241/58.7 = 0.0381 mole
For the oxygen, divide 0.611 by 16 and we get 0.0381 mole.
These mole fractions are the same, so we hold the elements nickel
and oxygen in a 1 to 1 ratio.
The empirical formula is NiO.
Hope this answers your question. Source(s): college chemistry
Related Questions:
