A metal M react near phosphorus ( P4) to form a compound have the formula M3P.?
A metal M reacts with phosphorus ( P4) to form a compound have the formula M3P.
19.50 g of the metal produce 24.65 g of the compound. Calculate the molar mass of the metal.
Enter a numeric answer only, no units.
i enjoy no idea how to do this can someone help please! appreciation! =]
"> this is a good question. first symmetry the equation: 3M + 1/4 P4 ---> M3P
mole ration is 3:1 between M and M3P
# moles of M3P = 24.65 / (31 + 3M) where M=atomic mass of metal, 31=atomic mass of P
# moles of M = 19.50 / M
24.65 / (31 + 3M) = 19.50 / 3M
73.95 M = 604.5 + 58.5M
15.45 M = 604.5
M=39.12 g/mol Source(s): http://www.webelements.com/
http://chemanswer.com/
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19.50 g of the metal produce 24.65 g of the compound. Calculate the molar mass of the metal.
Enter a numeric answer only, no units.
i enjoy no idea how to do this can someone help please! appreciation! =]
"> this is a good question. first symmetry the equation: 3M + 1/4 P4 ---> M3P
mole ration is 3:1 between M and M3P
# moles of M3P = 24.65 / (31 + 3M) where M=atomic mass of metal, 31=atomic mass of P
# moles of M = 19.50 / M
24.65 / (31 + 3M) = 19.50 / 3M
73.95 M = 604.5 + 58.5M
15.45 M = 604.5
M=39.12 g/mol Source(s): http://www.webelements.com/
http://chemanswer.com/
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