A metal M react next to nitrogen to form a compound have the formula M3N.?
A metal M reacts with nitrogen to form a compound have the formula M3N.
15.46 g of the metal produce 25.86 g of the compound. Calculate the molar mass of the metal.
Enter a numeric answer only, no units.
Answers:
6 M + 3 N2 = 2 M3N
mass N = 25.86 g - 15.46 g= 10.4 g
moles N = 10.4 g/ 14.0067 g/mol=0.743
the ratio between N and M is 1 : 3
moles M = 3 x 0.743 /1 =2.23
molar mass M = 15.46 g / 2.23 mol= 6.94 g/mol
M is Lithium and the aversion is
6 Li + N2 = 2 Li3N
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15.46 g of the metal produce 25.86 g of the compound. Calculate the molar mass of the metal.
Enter a numeric answer only, no units.
Answers:
6 M + 3 N2 = 2 M3N
mass N = 25.86 g - 15.46 g= 10.4 g
moles N = 10.4 g/ 14.0067 g/mol=0.743
the ratio between N and M is 1 : 3
moles M = 3 x 0.743 /1 =2.23
molar mass M = 15.46 g / 2.23 mol= 6.94 g/mol
M is Lithium and the aversion is
6 Li + N2 = 2 Li3N
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