A 5.00 g indication of pure Sn is head surrounded by the upper air and forms 6.34 g of metal oxide. What's the chemical formula?
The chemical formula of the tin oxide?
Answers:
The atomic mass of tin is 118.71 gm/mol, and the atomic mass of oxygen is 16 gm/mol.
When heated in air, the tin taste gains 1.34 grams of mass, which we will assume is all oxygen.
5 grams of Sn contains (5 gm)/(118.71 gm/mol) = 0.042 moles of Sn
1.34 grams of O contains (1.34 gm)/(16 gm/mol) = 0.084 moles of O.
The ratio of the number of moles of Sn to the number of moles of O within the sample of oxide is 0.042:0.084 = 1:2, so the formula of the oxide is SnO2.
Looking at the questions you enjoy posted, I believe you are having trouble understanding the argument of stoichiometry.
If you look at the periodic table it tells you that the freight of a tin atom is 118.7 atomic mass units and the weight of an oxygen atom is 16 atomic mass unit. What if I had a dozen atoms? The mass would be 118.7 x 12 atomic mass units and 16 x 12 atomic mass unit, respectively. Atomic mass units (amu) are very small unit of mass. It is more convenient to express the weights of 6.022 x 10^23 atoms (or molecules) in grams. 6.022 x 10^23 atoms (or molecules) is called one mole of atoms (or molecules). One mole have a mass in grams that is numericaly equal to the atomic mass unit. Thus, one mole of tin atoms has a mass of 118.7 grams. Likewise, one mole of oxygen atoms has a mass of 16 grams.
5.00 grams of tin is equal to 5 / 118.7 moles of tin. That works out to 0.04212 moles of tin.
The tin oxide weigh 6.34g so the oxygen weighed 6.34-5.00 g or 1.34 grams. 1.34 grams of oxygen atoms is equal to 1.34 /16 moles of oxygen atoms or 0.08375 moles of oxygen atoms.
The ratio of tin atoms :oxygen atoms = 0.04212 : 0.08375 or 1 : 2
The formula for tin oxide formed must be SnO2: one tin atom for every two oxygen atoms.
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Answers:
The atomic mass of tin is 118.71 gm/mol, and the atomic mass of oxygen is 16 gm/mol.
When heated in air, the tin taste gains 1.34 grams of mass, which we will assume is all oxygen.
5 grams of Sn contains (5 gm)/(118.71 gm/mol) = 0.042 moles of Sn
1.34 grams of O contains (1.34 gm)/(16 gm/mol) = 0.084 moles of O.
The ratio of the number of moles of Sn to the number of moles of O within the sample of oxide is 0.042:0.084 = 1:2, so the formula of the oxide is SnO2.
Looking at the questions you enjoy posted, I believe you are having trouble understanding the argument of stoichiometry.
If you look at the periodic table it tells you that the freight of a tin atom is 118.7 atomic mass units and the weight of an oxygen atom is 16 atomic mass unit. What if I had a dozen atoms? The mass would be 118.7 x 12 atomic mass units and 16 x 12 atomic mass unit, respectively. Atomic mass units (amu) are very small unit of mass. It is more convenient to express the weights of 6.022 x 10^23 atoms (or molecules) in grams. 6.022 x 10^23 atoms (or molecules) is called one mole of atoms (or molecules). One mole have a mass in grams that is numericaly equal to the atomic mass unit. Thus, one mole of tin atoms has a mass of 118.7 grams. Likewise, one mole of oxygen atoms has a mass of 16 grams.
5.00 grams of tin is equal to 5 / 118.7 moles of tin. That works out to 0.04212 moles of tin.
The tin oxide weigh 6.34g so the oxygen weighed 6.34-5.00 g or 1.34 grams. 1.34 grams of oxygen atoms is equal to 1.34 /16 moles of oxygen atoms or 0.08375 moles of oxygen atoms.
The ratio of tin atoms :oxygen atoms = 0.04212 : 0.08375 or 1 : 2
The formula for tin oxide formed must be SnO2: one tin atom for every two oxygen atoms.
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