At the back of a factory production row, boxes start from rest and slide down a 30o ramp 5.4 m long.?

At the end of a factory production line, boxes start from rest and slide down a 30o ramp 5.4 m long. If the slide is to pinch no more than 3.3 s, what is the maximum coefficient of friction between the box and the slide?
Answers:
The acceleration of the box down the ramp is F/m. The force F is the combination of gravity component along the ramp, less the friction force.

Fg = m*g*sinθ.

Fr = u*Fn, where Fn = regular force = m*g*cosθ

Total force on the box is m*g*(sinθ - u*cosθ)

The acceleration is F/m = g*(sinθ - u*cosθ)

The motion down the ramp is L = 0.5*a*t^2;

L = 0.5*g*(sinθ - u*cosθ)*t^2

for L = 5.4 m, g = 9.8 m/s^2, t = 3.3 s and θ = 30o solve for u
That depends on the mass of the box.

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